Two containers of equal volume contain same gas at pressure p1 and p2 and absolute temperature t1 and t2 respectively. On joining the vessels, the gas reaches a commmon pressure p and common temperature t. The ratio of p/t is
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Answered by
13
HEY DEAR ...
let the initial pressure and volume of two vessel be p and v. and the final pressure will be p’
the number of moles in the system will remain constant
n1+n2=n1’+n2’
pv/RT1 +pv/RT2 =p’v/RT +p’v/RT
from this p’ will be
p’=p(1/T1+1/T2)*T/2 -------------(1)
now as the change in volume is zero and assuming the loss in surrounding is zero the internal energy will be constant
internal energy before= internal energy after joining
CvPV/R +CvPV/R=CvP’(V1+V2)/R
P’=P--------(2)
Using 1 and 2
T=2T1T2/(T1+T2) answer
Hope , it helps ...
let the initial pressure and volume of two vessel be p and v. and the final pressure will be p’
the number of moles in the system will remain constant
n1+n2=n1’+n2’
pv/RT1 +pv/RT2 =p’v/RT +p’v/RT
from this p’ will be
p’=p(1/T1+1/T2)*T/2 -------------(1)
now as the change in volume is zero and assuming the loss in surrounding is zero the internal energy will be constant
internal energy before= internal energy after joining
CvPV/R +CvPV/R=CvP’(V1+V2)/R
P’=P--------(2)
Using 1 and 2
T=2T1T2/(T1+T2) answer
Hope , it helps ...
Answered by
8
The ans is 1/2(p1/t1 + p2/t2)
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