Question

Two copper wires A and B have the same mass. The resistance of wire A is 0.52 and
the length of wire B is double that of wire A. Find the resistance of wire B.

Please friends answer fastly​

Answer 1

Resistance of wire A = 0.52 ohm

Ratio of resistance of both the wires = p×L/A / p×L/A

$\rightarrow \frac{\cancel{p} \times \frac{l}{\cancel{A}}}{\cancel{p} × \frac{L}{\cancel{A}}} </p><p>\\ \rightarrow \frac{l}{L}$

We get the ratio of the resistance 1:2

Resistance of wire A : Resistance of wire B

0.52 : 2 × 0.52

0.52 : 1.04

Therefore, Resistance of wire B is 1.04 ohm

Answer 2

Answer:

Resistance of wire A = 0.52 ohm

Ratio of resistance of both the wires = p×L/A / p×L/A

→(p×l/A)/(p ×L/A)

→l/L

We get the ratio of the resistance 1:2

Resistance of wire A : Resistance of wire B

0.52 : 2 × 0.52

0.52 : 1.04

Therefore, Resistance of wire B is 1.04 ohm

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