Two copper wires of same length and different daiameter are heated from 0 to 100 degree celcious the change in length is linear.justify
Answers
Answer:
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Explanation:
HHeat given Q=mSΔT
The mass of thin rod is less than thick rod, so the rise in the temperature will be higher for thin rod.
ΔL=LαΔT.
So the rise will be more for higher ΔT. Thin rod will expand more.
Answer:
Heat given Q=mSΔT
Heat given Q=mSΔTThe mass of thin rod is less than thick rod, so the rise in the temperature will be higher for thin rod.
Heat given Q=mSΔTThe mass of thin rod is less than thick rod, so the rise in the temperature will be higher for thin rod. ΔL=LαΔT.
Heat given Q=mSΔTThe mass of thin rod is less than thick rod, so the rise in the temperature will be higher for thin rod. ΔL=LαΔT. So the rise will be more for higher ΔT. Thin rod will expand more.