Question

Two cross road each of width 10 m, cut at right angles through the center of a rectangular Park of land and breadth 300m and parallel to its side. Find the area of road. Also give this area in Hector ​

Answer 1

Answer:

Here, PQ = 10 m and PS = 300 m, EH = 10 m and EF = 700 m And KL = 10 m and KN = 10 m

Area of roads =

Area of PQRS + Area of EFGH – Area of KLMN

[∵ KLMN is taken twice, which is to be subtracted] =

PS x PQ + EF x EH – KL x KN

= (300 x 10) + (700 x 10) – (10 x 10) =

3000 + 7000 – 100 =

9,900 m2

Area of road in hectares, 1 m2 =1/10000 hectares

9,900 m2 =9900/10000

= 0.99 hectares

Now, Area of park excluding cross roads

= Area of park – Area of road

= (AB x AD) – 9,900 =

(700 x 300) – 9,900 =

2,10,000 – 9,900 =

2,00,100 m

= 200100 hectares

=

20.01

Step-by-step explanation:

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