two cross-roads each of 2 meters wide run at right angle through the center of the rectangular park of 72 m by 48 m such that each is parallel to one of the sides of rectangle. find the remaining portion of the park
Answers
Answer:
3220 m²
Step-by-step explanation:
*See attachment
With the two cross road running through. the park is divided into 4 smaller rectangles.
Find the dimensions of each of the smaller rectangles:
Length = (72 - 2) ÷ 2 = 35 m
Breadth = (48 - 2) ÷ 2 = 23 m
Find the area of each of the smaller rectangle:
Area = Length x Breadth
Area = 35 x 23 = 805 m²
Find the area of 4 of these smaller rectangles:
1 rectangle = 805 m²
4 rectangles = 805 x 4 = 3220 m²
Answer: The area of the remaining portion is 3220 m²
Step-by-step explanation:
Area of first crossroad which is rectangular = l×b
Hence area = 72m × 2m= 144 m²
Area of 2nd crossroad whuch is rectangular = 48m× 2m
= 96 m²
Area of middle part which is square =2m×2m
= 4m^2
Area of crossroads= (144+96) m² - 4 m²
=240 m² - 4 m²= 236 m²