Math, asked by vijjusetti, 1 year ago

two cross-roads each of 2 meters wide run at right angle through the center of the rectangular park of 72 m by 48 m such that each is parallel to one of the sides of rectangle. find the remaining portion of the park

Answers

Answered by TooFree
85

Answer:

3220 m²


Step-by-step explanation:

*See attachment

With the two cross road running through. the park is divided into 4 smaller rectangles.


Find the dimensions of each of the smaller rectangles:

Length = (72 - 2) ÷ 2 = 35 m

Breadth = (48 - 2) ÷ 2 = 23 m


Find the area of each of the smaller rectangle:

Area = Length x Breadth

Area = 35 x 23 = 805 m²


Find the area of 4 of these smaller rectangles:

1 rectangle = 805 m²

4 rectangles = 805 x 4 = 3220 m²


Answer: The area of the remaining portion is 3220 m²

Attachments:
Answered by Anonymous
30

Step-by-step explanation:

Area of first crossroad which is rectangular = l×b

Hence area = 72m × 2m= 144 m²

Area of 2nd crossroad whuch is rectangular = 48m× 2m

= 96 m²

Area of middle part which is square =2m×2m

= 4m^2

Area of crossroads= (144+96) m² - 4 m²

=240 m² - 4 m²= 236 m²



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