Question

Two cross-roads, each of width 10 m, run at right angles through the centre of a

rectangular park of length 80 m and breadth 50 m and parallel to its sides. Find the area

of the roads. Also find the cost of cementing the roads at the rate of Rs 150 per sq. m ?​

Answer 1

Step-by-step explanation:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

cost of the construction per sq.m =Rs.105

Answer 2

Step-by-step explanation:

Length of the 1st cross road parallel to the length = 80 m

Breadth of the 1st cross road parallel to the length = 10 m

Area of the 1st cross road = 80×10

= 800 sq m

Length of the 2nd cross road parallel to the breadth = 50 m

Breadth of the 2nd cross road parallel to the breadth = 10 m

Area of the 2nd cross road = 50×10

= 500 sq m

Area of the common part of the 2 cross roads with width 10 m that lies at the center of the rectangular park = 10×10

= 100 sq m

Area of the 2 cross roads = Area of the 1st cross road + Area of the 2nd cross road - Common area

⇒ (800 + 500) - 100

⇒ 1300 - 100

= 1200 sq m

Cost of constructing the roads = Rs. 105 sq m

Total cost of constructing the road = 1200*105

= Rs. 126000

hope it will help you ❣️❣️