Two cross-roads, each of width 10 m, run at right angles through the centre of a
rectangular park of length 80 m and breadth 50 m and parallel to its sides. Find the area
of the roads. Also find the cost of cementing the roads at the rate of Rs 150 per sq. m ?
Answers
Step-by-step explanation:
width =5 m
length of first parallel road 70 m
area of first road 70×5=350 sq.m
length of second road 45 m
area of second road =45×5=225 sq.m
area of the common part of cross road with 5 m width that lies at the
center of the park 5×5 = 225 sq.m
area of roads = area of first road +area of second cross road−common area
=(350+225)−25
=575−25
=550sqm
cost of the construction per sq.m =Rs.105
Step-by-step explanation:
Length of the 1st cross road parallel to the length = 80 m
Breadth of the 1st cross road parallel to the length = 10 m
Area of the 1st cross road = 80×10
= 800 sq m
Length of the 2nd cross road parallel to the breadth = 50 m
Breadth of the 2nd cross road parallel to the breadth = 10 m
Area of the 2nd cross road = 50×10
= 500 sq m
Area of the common part of the 2 cross roads with width 10 m that lies at the center of the rectangular park = 10×10
= 100 sq m
Area of the 2 cross roads = Area of the 1st cross road + Area of the 2nd cross road - Common area
⇒ (800 + 500) - 100
⇒ 1300 - 100
= 1200 sq m
Cost of constructing the roads = Rs. 105 sq m
Total cost of constructing the road = 1200*105
= Rs. 126000
hope it will help you ❣️❣️