Math, asked by farzanaSayed, 3 months ago

two cross roads each of width 10m cut at right angles through the centre of a rectangular park of length 700m and breadth 300m and parallel to it's sides find the area of the roads and also the cost of constructing the roads at the rate of rs110per m square​

Answers

Answered by nishathakur5755
2

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750

Step-by-step explanation:

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