Question

two cross roads, each of width 5 m, cut at right angles through the centre of a rectangular park of length 500 m and breadth 200 m and parallel to its sides. find the area if the roads​

Answer 1

Answer:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

road−common area

=(350+225)−25

=575−25

=550sqm

cost of the construction per sq.m =Rs.105

total cost=550×150=57750

Answer 2

Answer:

•● ᴀɴsᴡᴇʀ●•

Given that,

Width = 5m

Length = 500m and

breadth = 200m

According to the questions

• Area of the field= 500 × 200 = 100000

• Area of the road parallel to the length = 5×200 = 1000

• The Area of the road parallel to the width

=> 5 × 500 = 2500

♡ ᴍɪss_ɪɴɴᴏᴄᴇɴᴛ♡