Question

Two cross roads,each of width 5m ,run at right angles through the centre of a rectangular park of length 70m and breadth 45m and parallel to its sides.Find the area of the roads. Also find those cost of constructing the roads at the rate of rupees 105 per month square

Answer 1

area of the roads is (350+225-25)meter square =550 metres square

therefore cost of construction of road =
105*550 = 57750

hope this answer helped u.

Answer 2

Answer:

Total Cost of construction = Rs. 57750

Step-by-step explanation:

Length of the rectangular park AD = 70 m

Breadth of the rectangular park CD = 45 m

Area of the rectangular park = Length x Breadth = 70 m x 45 m = 3150 m²

Area of the road EFGH = 70 m x 5 m = 350 m²

Area of the road JKIL = 45 m x 5 m = 225 m²

Clearly area of MNOP is common to the two roads.

Thus, Area of MNOP = 5 m x 5 m = 25 m²

Hence,  Area of the roads = Area (EFGH) + Area (JKIL) – Area (MNOP)

                                          = (350 + 225) – 25  

                                          = 550 m²

Again, it is given that the cost of constructing the roads = Rs. 105 per m²

Therefore,  Cost of constructing 550 m² area of the roads = Rs. (105 x 550) = Rs. 57750.