Math, asked by atharvagaikwad51, 3 months ago

Two cross-roads, each of width 5m, run at right angles through the centre of a rectangular park

of length 80m and breadth 50m and parallel to its side. Find the area of roads.​

Answers

Answered by MiraculousBabe
30

Answer:

Solution:-

Length of the 1st cross road parallel to the length = 70 m

Breadth of the 1st cross road parallel to the length = 5 m

Area of the 1st cross road = 70×5 

= 350 sq m

Length of the 2nd cross road parallel to the breadth = 45 m

Breadth of the 2nd cross road parallel to the breadth = 5 m

Area of the 2nd cross road = 45×5 

= 225 sq m

Area of the common part of the 2 cross roads with width 5 m that lies at the center of the rectangular park = 5×5

 

= 25 sq m

Area of the 2 cross roads = Area of the 1st cross road + Area of the 2nd cross road - Common area

⇒ (350 + 225) - 25

⇒ 575 - 25 

= 550 sq m

Cost of constructing the roads = Rs. 105 sq m

Total cost of constructing the road = 550×105

= Rs. 57750

Answered by SandySanjeet
5

Step-by-step explanation:

Rs.57750

Pta nhi correct ya wrong

Rapunzel ko plich Brainlist dedo yll..

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