Two cross roads each of width 5m runs at right angles through the centre of a rectangle park lengh 80 and breadth 35 and Parralel to its side. Find the area of the roads
Answers
5 (80 + 30) = 5 (110) = 550 m^2
Two cross roads each of width 5m runs at right angles through the centre of a rectangle park lengh 80 and breadth 35 and Parralel to its side. Find the area of the roads
width = 5m
length of first parallel road 70 m
area of first road 70 × 5 = 350 sq .m
length of second road 45m
area of second road = 45 × 5 = 255 sq .m
area of the common part of cross road with 5m width that lies at the
centre of the part 5× 5 = 255 sq.m
area of roads = area of first road + area of second cross road - common road
= (350 + 255 ) - 25
= 575 - 25
= 550 sq .m
cost of the construction per sq .m = Rs . 105
total cost = 550 × 105 = Rs . 57750