two crossroad each of width 3m,run at right angles and parallel to the sides of a rectangular plot of dimensions 80×60m.find the area of the roads.
Answers
Answer:
3×80=240, 3×60=180
Step-by-step explanation:
sum=240+180=420-3×3=420-9=411
area of road 411
The area of the road is 411 m².
Step-by-step explanation:
Consider the provided information.
It is given that two crossroad each of width 3 m, run at right angles and parallel to the sides of a rectangular plot of dimensions 80×60 m.
Now consider the figure:
The area of road = Area of IJKL + Area of EFGH - Area of PQRS
For the rectangle IJKL the length is 60 m and breath is 3 m.
For the rectangle EFGH the length is 3 m and breath is 80 m.
For PQRS the length and breath is 3 m.
The area of road = 60×3 + 3×80 - 3×3
The area of road = 180 + 240 - 9
The area of road = 411 m²
Hence, the area of the road is 411 m².
#Learn more
A field 70 M long and 45 M wide has to cross roads in the centre.each road is 5 M wide find the area of the remaining field.
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