Two cubes each of side 10cm are joined from end to end, forming a rectangular shaped solid. Find the surface area of the resulting rectangular shaped solid.
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The two cobes will make a cuboid of l= 6cm b= 12 cm and h=6 cm.
After applying the tsa of coboid i.e. 2 (lb+bh+hl) we have
2 (6×12+6×12+6×6)
2 (72+72+36)
2 (180)
=360 cm^2
After applying the tsa of coboid i.e. 2 (lb+bh+hl) we have
2 (6×12+6×12+6×6)
2 (72+72+36)
2 (180)
=360 cm^2
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