Two cubes each of volume 125cm are joined together end to end find the surface area of resulting Cuboid
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volume of the cube =a^3
=125=a^3
=a=
![\sqrt[3]{125}](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B125%7D+ "\sqrt[3]{125}")
a=5
therefore the CSA of 1 cube
=4a^2
=4×5^2
=4×25
=100
CSA of both the cubes=100×2
=200
the area of the side panes=2a^2
=2×5^2
=2×25
=50
hence the area of the total cuboid formed =200+50
=250cm^2
=125=a^3
=a=
a=5
therefore the CSA of 1 cube
=4a^2
=4×5^2
=4×25
=100
CSA of both the cubes=100×2
=200
the area of the side panes=2a^2
=2×5^2
=2×25
=50
hence the area of the total cuboid formed =200+50
=250cm^2
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