Question

two cubes each of volume 27 cm cube are joined end to end to form a solid find the surface area of resulting cuboid

Answer 1

Hlo friend.. Cutiepie Here.

Here is ur answer :

Volume of cube = 27 cm³

Let the side be a

( side)³ = 27

a³ = 27

$a = \sqrt[3]{27}$

$a = 3$

Side = 3 cm


Two cubes each of volume 27 cm cube are joined end to end to form a solid.

So, both of cubes have side 3 cm.

By joining two cubes the cuboid will form.

Length l of cuboid = 3 + 3 = 6 cm

Breadth b of cuboid = 3 cm

Height h of cuboid = 3 cm



Lateral surface area of cuboid =

$2 \times height \: (length + breadth)$


$= 2h(l + b)$


$= 2 \times 3(3 + 6)$


$= 6 \times 9$

$= 54 {cm}^{2}$

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Total surface area of cuboid

$= 2(length \times breadth + breadth \times height + height \times length)$


$= 2(lb + bh + hl)$


$= 2(6 \times 3 + 3 \times 3 + 3 \times 6)$


$= 2(18 + 9 + 18)$


$= 2 \times 45$

$= 90 \: {cm}^{2}$

_______________________

HOPE IT HELPS YOU..

:-)

Answer 2

Answer: 54cm^2 & 90cm^2

Step-by-step explanation:

volume of one cube= s^3

27=s^3

s=∛27

s=3 cm

now length of the resulting cuboid=3+3=6 cm

breath=3 cm

height=3 cm

now ,

lateral surface area of cuboid =2h(l+b)

2×3(6+3)

6(9)

54 cm^2

and

total surface area of cuboid = 2(lb+lh+bh)

2(18+18+9)

2(45)

90 cm^2