Two cubes each of volume 27 cm3 are joined end to end to form a solid. Find the surface area of the resulting cuboid.
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Let the length of the side of cube be ‘a’ cm.
Volume of each cube = 27 cm3
Volume of cube = a3
∴ a3 = 27 cm3
⇒ a = (27 cm3)1/3
⇒ a = 3 cm
Length of a side of cube = 3 cm
Since, two cubes are joined and a cuboid is formed so,
Length of cuboid = l = 2a = 2 × 3 cm = 6 cm
Breadth of cuboid = b = a = 3 cm
Height of cuboid = h = a = 3 cm
Surface area of cuboid = 2 × (l × b + b × h + l × h)
∴ Surface area of resulting cuboid = 2 × (6 × 3 + 3 × 3 + 6 × 3) cm2
= 2 × (18 + 9 + 18) cm2
= 2 × 45 cm2
= 90 cm2
So, surface area of resulting cuboid is 90 cm2
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