Question

Two cubes each of volume 343 are joined end to end the total surface area of resulting cuboid is

Answer 1

Solution: Volume of cube = x³

→ 343 unit³ = x³

→ (7 × 7 × 7) unit³ = x³

→ 7 unit = x

Now such two cubes are joined together. Then cuboid formed has,

• l = (7 + 7) = 14 units

• b = h = 7 units

→ Volume of cuboid = lbh

→ 14 × 7 × 4 unit³ = 686 unit³

→ Surface area of cuboid

= 2(lb + bh + hl)

→ 2(14 × 7 + 7 × 7 + 7 × 7) unit²

→ 2(98 + 49 + 98) unit²

→ 2(245) unit² = 490 unit²

Answer 2

Answer:

The total surface area of the cuboid is  490 $unit^{2}$.

The total surface area of the cuboid  = 2(lb+bh+lh) where l,b, and h are the dimensions of the cuboid.

The volume of the cube = $l^{3}$ where l is the side length of the cube.

Step-by-step explanation:

Given, the volume of the cube = 343

           which implies $l^{3} = 343$

we obtain l = 7 units.

When we place two such cubes side-by-side the resultant dimensions are

l = 14 units.

b = 7 units.

h = 7 units.

Now we can compute the total surface area = 2(lb+bh+lh) = $2(14*7 + 7*7 + 14*7) = 490 unit^{2}$.