Question

Two dielectric slabs of dielectric constant k1 and k2 are filled between two plates each of area a of the parallel plate capacitor.Find the net capacitqnce of the capacitor

Answer 1

$\frac{\varepsilon_0\times A(k_1 + k_2)}{2d}$

Explanation:

Capacitance when distance is introduced in between the capacitor is given By,

 C = $K\times \frac{\varepsilon_0\times A}{d}$

Parallel combination of two capacitor ,each with plate area \frac{A}{2}

and separation between the plate d.

Thus ,

The net capacitance is,

$c = c_1 + c_2$

$c = \frac{\varepsilon_0\times(\frac{A}{2})\times k_1}{d} + \frac{\varepsilon_0\times(\frac{A}{2})\times k_2}{d}$

= $\frac{\varepsilon_0\times A(k_1 + k_2)}{2d}$