Question

Two cubes each of volume 64 cm cube or joined end to end together find the total surface area of the resulting cuboid...

Answer 1

Hello Friend....


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The answer of u r question is....

Ans:


Given,


Volume of each cube = 64cm^3

$= {a}^{3} = {64cm}^{3}$


$= {a}^{3} = {4}^{3}$
$a = 4cm$

length of the cuboid =4+4= 8cm

Breadth of the cuboid =4 cm

Height of the cuboid = 4 cm

T.S.A of cuboid =2(lb+bh+hl)

=2(8×4+4×4+4×8)

=2(32+16+32)

=2(80)

$= {160cm}^{2}$


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Answer 2

Given that,

Volume of cube = 64cm³

→ s³ = 64

→ s³ = (4)³

→ s = 4 cm

So, the side of the cube is 4 cm

When two such cubes are joined to make a cuboid, then the Breadth and Height remain 4 cm, but the length becomes double, that is 8 cm.

Now,

Length of cuboid = l = 8 cm

breadth = b = 4 cm

height = h = 4 cm

Total surface area of the cuboid = 2(lb + bh + hl)

= 2[ (8 x 4) + (4 x 4) + (4 x 8) ]

= 2[ 32 + 16 + 32]

= 2[80]

= 160 cm²

Therefore the Total surface area of the resulting Cuboid is 160 cm²

Hope it helps!!