two cubes each of volume 64 CM square are joined end to end find the surface area of the resulting cuboid
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volume of a cube is equal to 64 CM sq
volume od a cube=a×a×a
64sq cm=a×a×a
a= cube root 64
a=4
the dimensions of the cuboid formed by joining the two smaller cubes are
length=4+4=8
breadth=4
height=4
volume od a cube=a×a×a
64sq cm=a×a×a
a= cube root 64
a=4
the dimensions of the cuboid formed by joining the two smaller cubes are
length=4+4=8
breadth=4
height=4
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