Two cubes each of volume 64cm are joined end to end find the surface area and volume of the resulting cuboid
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2
In question there is cm ³
Step-by-step explanation:
Given, volume of each cube is 64 cm³
⇒s³=64
⇒s=∛64
⇒s=4 cm.
When two cubes are joined ,
the length of the resulting cuboid(l) = side + side = 4+4 = 8 cm
its breadth(b) = side = 4cm
And its height(h) = side = 4cm
Total surface area of a cuboid = 2(lb+bh+hl)
⇒TSA=2[(8)(4)+(4)(4)+(4)(8)]
⇒TSA=2(32+16+32)
⇒TSA = 2(80)
⇒TSA = 160 cm²
∴ The surface area of the resulting cuboid is 160 cm².
Volume of resulting cuboid = lbh = 8*4*4=128 cm³
Answered by
11
Given:-
- Two cubes each of volume 64cm are joined end to end.
To find:-
- Find the surface area and volume of the resulting cuboid.?
Solutions:-
- Let the side of the cube be x cm.
We know that,
- Volume of cube = side³
=> 64 = (x)³
=> 64 = x³
=> √4 × 4 × 4 = x
=> 4cm = x
So, Dimensions of cuboid
- Length = 4 + 4 = 8cm
- Breadth = 4cm
- Height = 4cm
Now,
- Total surface area = 2(lb + bl + lh)
=> 2(8 × 4 + 4 × 4 + 4 × 8)
=> 2(32 +16 + 32)
=> 2(80)
=> 160cm²
Hence, the total surface area of cuboid is 160cm².
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