Question

two cubes each of volume 64cm3 are joined end to end together find the surface area of the resulting cuboid

Answer 1

heya!

here's ur answer...

volume of 1cube=64cm³

side³=64cm³

side=³√64

side=4cm

therefore total volume of both cubes=64×2

=128cm³

so the length of the new cuboid is=4+4

=8cm

TSA of the cuboid=2(lb+bh+lh)

=2{(8×4)+(4×4)+(8×4)

=2(32+16+32)

=2×80

=160cm²

hope this helps...

(^^)

Answer 2

volume of each cube = 64cm³

volume = side³
64 = side³
$side \: = \sqrt[3]{64}$
side = 14cm

given ,
two cubes of these kinds are joined end to end.

therefore,
measurements of the resulting cuboid,

length = 8cm
breadth = 4cm
height = 4cm

surface area = 2( lb + bh + lh )
= 2( 32 + 16 + 32 )
= 2( 80)
= 160 cm²