Question

two cubes each of volume 8 cm3 are joining end to end, then what is the surface area of resulting cuboid

Answer 1

Hi friend
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Your answer
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Volume of cubes = 8 cm³

Measure of each side = √8 cm = 2 cm

The two cubes are placed end to end.

Then,
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Dimensions of the resulting cuboid =>

Length = (2+2) cm = 4 cm

Breadth = Height = 2 cm

Total surface area of the cuboid = 2(lb × lh × bh)

=> [2 × { (4×2) + (4×2) + (2×2)}] cm²

=> [ 2× ( 8 + 8 + 4)] cm²

=> [2 × 20] cm²

=> 40 cm²

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Answer 2

Side of the cube, a = $\bf\huge\sqrt[3]{8}$  = 2 cm

Now, the length l of cuboid  = 4 cm

breadth, b = 2 cm

height, h = 2 cm

Surface area of cuboid

= 2(l × b + b × h + h × l)  

= 2(4 × 2 + 2 × 2 + 2 × 4)

= 2 × 20

= 40 cm^2