Question

Two cubes have their volume in ratio 1:2, find the ratio of their surface area?​

Answer 1

Explanation:

1 : 2^2/3

volume V = l^3

V1 : V2 = (l1 : l2) ^3

l1 : l2 = (V1 : V2)^ 1/3 = (1 : 2)^ 1/3

Surface Area of cube A =6l^2

A1 : A2 = (l1 :l2)^2 = (1 : 2)^ 2/3

Answer 2

Answer:

(1/4)^1/3

Explanation:

V1 / V2 = 1/2

Since volume of cube = a^3

Let edge of V1 be a

And edge of V2 be b

So

From here

a^3/b^3= 1/2

(a/b)^3 = 1/2

a/b = (1/2)^1/3

Now as for surface area

We know surface area(S) of a cube is 6a^2

So

S1/S2 = 6a^2 / 6b^2

= a^2/b^2

= (a/b)^2

={(1/2)^1/3}^2

=(1/2)^2/3

= (1/4)^1/3