Question

Two current carrying conductor placed on smooth surface as shown in figure then for conductor CD where acceleration and angular acceleration respectively

Answer 1

Answer:

ANSWER

The force acting on the elementary portion of the current carrying conductor is given as,

dF=i(dr)Bsin90

0

dF=iBdr

The torque applied by dF about O=dτ=rdF

⇒ the total torque about O=τ=∫dτ=∫r(iBdr)

⇒τ=iB∫

0

L

rdr=

2

iBL

2

The angular acceleration α=

I

τ

⇒α=(

2

iBL

2

)/(

3

mL

2

)=

2m

3ib

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