# Two cyclists cover the same distance in 15 km/hr and 16 km/hr, respectively. Find the distance traveled by each, if one takes 16 min longer than the other does? Plz answer!!! I will mark the best answer as brainlest!! ;D

## Answers

Answered by

43

Hey buddy here is ur ans

Let time = t

So we equate the equal distance like so

10 kmph x t + (40/60 x 10)= 15 kmph x t

10t + 6,67 = 15t

5t = 6,67

t = 1,33 hours

therefore distance = s x t

= 10 x 1,33 + 6,67 = 20 km

= 15 x 1,33 = 20 km

Let time = t

So we equate the equal distance like so

10 kmph x t + (40/60 x 10)= 15 kmph x t

10t + 6,67 = 15t

5t = 6,67

t = 1,33 hours

therefore distance = s x t

= 10 x 1,33 + 6,67 = 20 km

= 15 x 1,33 = 20 km

Answered by

18

**Step-by-step explanation:**

let the required distance be x km.

therefore x/15-x/16=16/60

---> 16x-15x=64

--> x=64

hence the required distance =64 km

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