Two cyclists cover the same distance in 15 km/hr and 16 km/hr, respectively. Find the distance traveled by each, if one takes 16 min longer than the other does? Plz answer!!! I will mark the best answer as brainlest!! ;D
Answers
Answered by
43
Hey buddy here is ur ans
Let time = t
So we equate the equal distance like so
10 kmph x t + (40/60 x 10)= 15 kmph x t
10t + 6,67 = 15t
5t = 6,67
t = 1,33 hours
therefore distance = s x t
= 10 x 1,33 + 6,67 = 20 km
= 15 x 1,33 = 20 km
Let time = t
So we equate the equal distance like so
10 kmph x t + (40/60 x 10)= 15 kmph x t
10t + 6,67 = 15t
5t = 6,67
t = 1,33 hours
therefore distance = s x t
= 10 x 1,33 + 6,67 = 20 km
= 15 x 1,33 = 20 km
Answered by
18
Step-by-step explanation:
let the required distance be x km.
therefore x/15-x/16=16/60
---> 16x-15x=64
--> x=64
hence the required distance =64 km
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