Question

Two cyclists cover the same distance in 15 km/hr and 16 km/hr respectively. Find
the distance travelled by each, if one takes 16 min longer than the other does?​

Answer 1

Answer:

7..1km

Step-by-step explanation:

Let's give names to the two cyclists.

Let's call the first cyclists to be 'A' and second to be 'B'.

Cyclists 'A' is traveling at a speed of 16 km/hr.

Now ,assuming that the distance covered by A and B is x km.

We need to find time , because we don't know that.

But we know the formula of time , that is :

$\sf \boxed{\sf \implies \: time = \dfrac{distance}{speed} }$

→ Assuming distance covered by A and B = x

$\sf time \: taken \: by \: A \: with \: respect \: to \: 1km \: = \frac{1km}{15}$

$\sf \implies \: 4 \: minutes$

and

$\sf \: time \: taken \: by \: B \: with \: respect \: to \: 1km = \frac{1km}{16}$

$\sf \implies \: 3.75 \: minutes$

Total time taken by A and B respectively = 6x and 3.75x

Now,

$\sf \: 6x - 3.75x = 2.25x$

According to the question :

$\sf \: 2.25x = 16minutes$

$\implies \sf \: x = \frac{16}{2.25}$

$\sf \implies \: x = 7.1$

Total distance covered by A and B = 7.1 km

What you need to know ?

• Speed = Distance /time