Physics, asked by lakshmikumari72, 9 months ago

A ball is projected in a vertical plane with a speed of 20 m/s from the top of a tower of height 84m at
an angle of 53° with the horizontal, The time after which it reaches the ground is ​

Answers

Answered by ks2289980
0

Answer:Initial vertical speed is u=5m/s×sin53  

0

=4m/s

so if the final vertical  velocity being v at a height h then v  

2

=u  

2

−2gh will give us v=  

16−20×0.45

​  

=  

7

​  

m/s

the horizontal velocity remain constant and given as V  

x

​  

=5m/sCos53  

0

=3m/s

so the speed at the said instant will be V=  

V  

x

2

​  

+v  

2

 

​  

=  

9+7

​  

=4m/s

Explanation:

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