Math, asked by shloksing07, 10 months ago

Two cyclists start from the middle of a 200m track and move in opposite directions towards the end of the track at 5m/s and 10m/s respectively. At the time when a cyclist first reaches the end, both cyclists turn around and start moving towards each other with their initial speeds. During this motion, a fly moves at a speed of 17 m/s, between the 2 cyclists, landing on one cyclist and then moving to the next continuously. How much distance has the fly covered when the two cyclists meet again?

Answers

Answered by amitnrw
9

Given :  Two cyclists start from the middle of a 200m track and move in opposite directions towards the end of the track at 5m/s and 10m/s respectively.  

To find : distance has the fly covered when the two cyclists meet again?

Solution:

Distance between cyclist & track end = 200/2 = 100 m

Cyclist with more speed 10m/s will reach end first

time taken = 100/10  = 10 sec

Distance covered by other cyclist in 10 seconds = 10 * 5 = 50 m

Distance between cyclist  = 100 + 50 = 150 m

Time taken to meet each other = 150/(10 + 5)  = 10 sec

Total time = 10 + 10 = 20 secs

Speed of fly = 17 m/s

Distance Covered by fly = 17 * 20 = 340 m

Distance Covered by fly = 340 m

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