two cylinder gas has same volume is a diameter are in the ratio 3:4 find the ratio of the corresponding heights
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Answered by
1
Let r and R are the radius of base of two cylindrical jars.
Let h and H are the heights of the two cylindrical jars.
Now,
Diameter of the first jar/Diameter of the second jar = 3/4
=> 2πr/2πR = 3/4
=> r/R= 3/4
Again,
Volume of the first jar/Volume of the second jar = 1 {since same amount of the milk contain}
=> πr2 h/πR2 H = 1
=> r2 h/R2 H = 1
=> (r2 /R2 )*(h/H) = 1
=> (3/4)2 * (h/H) = 1
=> (9/16) * (h/H) = 1
=> h/H = 16/9
=> h : H = 16 : 9
Answered by
1
Let radii be 3k and 4k
We are given Л(3k)^2h1/Л(4k)^2h2 = 1
so, 9k^2*h1/16k^2*h2=1
so, h1/h2 = 16/9
So, Ratio of heights = 16:9
We are given Л(3k)^2h1/Л(4k)^2h2 = 1
so, 9k^2*h1/16k^2*h2=1
so, h1/h2 = 16/9
So, Ratio of heights = 16:9
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