Two cylindrical containers namely A and B have radii of base 21 cm and heights 30 cm, are
full of icecream. Nandan filled cylindrical cups and Nimisha filled conical cups with
icecream from container A and B respectively. Both type of cups have radius ol base 5.cm
22)
12!
and height 4 cm. T =
T-
Answer the following. .
a) How many icecream filled cups Nandan will have?
b) Will Nimisha have more number of cups than Nandan? If yes, how much number more?
Answers
Answer:
Answer:
Diameter of the ice cream cone will be 6cm
Step-by-step explanation:
Let r, h be the radius and height of the cylindrical container, it is given that diameter=12cm, then r will be equal to 6cm.
Now, ,volume of the cylindrical container={\pi}r^{2}hπr
2
h
={\pi}(6)^{2}15π(6)
2
15 ={\pi}(36)(15)π(36)(15)
=540{\pi}540π
Volume of 10 ice cream cones is = 540{\pi}540π , then
Volume of 1 ice cream cone will be=54{\pi}54π
Volume of the cone will be given as:\frac{2}{3}{\pi}R^{3}+\frac{1}{3}{\pi}R^{2}H
3
2
πR
3
+
3
1
πR
2
H =54{\pi}54π , where R and H is the radius and height of the hemispherical cone.
Also, it given that H=2D, therefore, H=2(2R)=4R
⇒Volume=\frac{2}{3}R^{3}+\frac{1}{3}R^{2}(4R)=54
3
2
R
3
+
3
1
R
2
(4R)=54
⇒6R^{3}=1626R
3
=162
⇒R^{3}=27R
3
=27
⇒R=3cmR=3cm
Therefore, diameter of the ice cream cone is= 2R=2(3)=6cm