How many two digit numbers leave the remainder 1 when divided by 5.
Answers
Answer:
The two-digit numbers which leave the remainder 1 when divided by 5 are ;
11,16,21,26,.......86,91,96
In this A.P :
a = 11
d = 16-11 = 5
l = 96
n = ?
Tn = a+(n-1)d
96 = 11+(n-1)5
n-1 = 85/5
n = 17+1
n = 18
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Hence their are 18 two digit numbers which when divided by 5 leaves remainder 1.
There are 18 numbers that leave the remainder 1 when divided by 5.
Step-by-step explanation:
Consider the provided information.
A number is divisible by 5 if it ends with 0 or 5.
That means if the number ends with 1 or 6 it will gives the remainder 1 when divided by 5.
Thus, for the unit place we have 2 digits 1 or 6.
For ones place we have 9 digits: 1, 2, 3, 4, 5, 6, 7, 8,or 9
Thus, the total number of digits are: 9×2=18
Hence, there are 18 numbers that leave the remainder 1 when divided by 5.
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