Question

Two cylindrical vessels are filled with milk. The radius of one vessel is 15cm and height is 40cm and the radius of other vessel is 20cm and height is 45cm. Find the radius of another cylindrical vessel of height 30cm which may just contain the milk which is in the two given vessels

Answer 1

Answer:

Volume of first cylindrical vessel + volume of second cylindrical vessel = volume of big cylindrical vessel.

3. 14* 15*15*40 + 3. 14 * 20*20*45 = 3. 14 * 30 * r * r

28260 + 56520 = 94.2 * r * r

84780 = 94. 2 * r * r

84780 / 94. 2 = r * r

900 = r2

R = 30 cm

Step-by-step explanation:

Answer 2

$\huge \underline \mathbb {SOLUTION:-}$

Given:

• Radius of 1st cylinder = 15cm
• Height of 1st cylinder = 40 cm

• Radius of 2nd cylinder = 20 cm
• Height of 2nd cylinder = 45 cm

Also, height of new cylinder = 30 cm

ExPlanation:

Let the radius of new cylinder be r cm.

Sum of volumes of 1st and 2nd cylinder = volume of new cylinder

π × 152× 40 + π × 202× 45 = πr²× 30

⇒(225 × 40 + 400 × 45) = r² × 30

⇒ 9000 + 18000 = r² × 30

⇒27000 = r² × 30

⇒r² = 900

⇒r² = 302

⇒r = 30 cm

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$