Find the sum of alleven numbers between 1 to 350
Answers
Answered by
0
Answer:
30800 is the sum of all even no between 1 and 350.
Step-by-step explanation:
➡️ To find sum of all even no between 1 to 350.
➡️ First even no 'a' = 2
➡️ Common difference 'd' = 2.
➡️ Last term = 350
➡️ Total no of terms = n
➡️ Last term = a + (n - 1) d
350 = 2 + (n - 1) 2
350 = 2 + 2n - 2
350 = 2n
➡️ n = 175.
➡️ Sum of even terms = n/2(a + l)
Sum of even term = 175/2 (352)
Sum of even terms = 175 ☓ 176
➡️ Sum of even terms = 30800
Answered by
0
sum of all the even nos. from 1 to 350 is
=2+4+6+8+10+12+14+16+18.........+350
using the ap formula
a=2
d=2
l=350
now,to find the no. of terms
350=2+(n-1)d
=2+(n-1)2
350=2n
n=350/2
=175
now to find the sum,
s=n/2[a+l]
=175/2[2+350]
=175/2×352
=175×176
=30800
=2+4+6+8+10+12+14+16+18.........+350
using the ap formula
a=2
d=2
l=350
now,to find the no. of terms
350=2+(n-1)d
=2+(n-1)2
350=2n
n=350/2
=175
now to find the sum,
s=n/2[a+l]
=175/2[2+350]
=175/2×352
=175×176
=30800
Similar questions