Question

Two dice are numbered 1, 2, 3, 4, 5, 6 and 1, 1, 2, 2, 3, 3, respectively. They are thrown, and the sum of the numbers on them is noted. Find the probability of getting sum equal to 5.​

Answer 1

Answer:

Probability of getting sum equal to 5 is 1/6.

Solution

Sample Space of the Event

(1,1)(2,1)(3,1)(4,1)(5,1)(6,1)

(1,1)(2,1)(3,1)(4,1)(5,1)(6,1)

(1,1)(2,2)(3,2)(4,2)(5,2)(6,2)

(1,2)(2,2)(3,2)(4,2)(5,2)(6,2)

(1,3)(2,3)(3,3)(4,3)(5,3)(6,3)

(1,3)(2,3)(3,3)(4,3)(5,3)(6,3)

Total Number of outcomes n(S)  = 36.

We have to find the probability of getting sum equal to 5.

$\bigstar$Favorable outcomes are = (4,1) , (4,1) , (3,2) , (3,2) , (2,3) , (2,3).

Number of Favorable outcomes = 6.

$\sf Probability \: of \: an \: event = \dfrac{Number \: of \: favorable \: outcomes }{Total \: number \: of\: outcomes}$

$\sf Probability = \dfrac{6}{36} = \dfrac{1}{6}$