Two dice are rolled. Find the probability that the sum is equal to 4. (Ans-1/4)
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Total possible outcomes- (1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)=36
Total favourable outcomes=(1,3),(2,2),(3,1)=3
probability=3/36
=1/12
Total favourable outcomes=(1,3),(2,2),(3,1)=3
probability=3/36
=1/12
Anonymous:
wrong
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