Two dice are rolled. if the two faces are different, the probability that one is a six is
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n(S)=36
A={(1,6) (2,6) (3,6) (4,6) (5,6) (6,6)}
n(A)=6
p(A)=n(A)/n(S)
=6/36
A={(1,6) (2,6) (3,6) (4,6) (5,6) (6,6)}
n(A)=6
p(A)=n(A)/n(S)
=6/36
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