Question

Two dice are rolled once. Find the probability of getting such numbers on two dice, whose product is a perfect square.
OR
A game consists of tossing a coin 3 times and noting its outcome each time. Hanif wins if he gets three heads or three tails, and loses otherwise. Calculate the probability that Hanif will lose the game.

Answer 1

Answer:

Perfect squares can be either 1,4,9,16,25,36 in this scenario.

1=1*1 (1 way)

4=1*4;2*2 (3 ways)

9=3*3 (1 ways)

16=4*4 (1 ways)

25=5*5 (1 ways)

36=N/A (0 ways)

Number of ways to get two numbers whose product is a perfect square=1+3+1+1+1+0=7

Pr(Product is perfect square)=7/36

AND

Pr(Lose)=1-Pr(Win)=$1-(0.5)^3-(0.5)^3=0.75$

I think these are the correct answers.

Hope these help :)

Step-by-step explanation: