Two dice are rolled once. Find the probability of getting such no.on two dice,whoes product is 1
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S= total no. of faces
n(S)= 36
E=getting a no. whose product is 1
n(E)= 1 {(1,1)}
P(E)=n(E)/n(S)
:. P(E)= 1/36
Therefore, the probability of getting a no. whose product is 1 is 1/36
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