Two dice are rolled one after the other. What is the probability of getting a prime number on the 1st die and a divisor of 4 on the 2nd die?
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total no of outcomes=36 {(1,1) (1,2)........(1,6) (2,1) (2,2)......(2,6).......(6,6)}
sample space-{(2,4) (3,4) (5,4)}
probability=no of favourable outcomes/total outcomes
=3/36
=/12
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