Two dice are rolled simultaneously. Find the probability of getting the sum of numbers on the on the two faces divisible by 3 or 4?
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Answered by
3
A = { sum should be divisible by 3 or 4 }
A = {(1,2)(1,3)(1,5)(2,1)(2,2)(2,4)(2,6)(3,1)(3,3)(3,5)(3,6)(4,2)(4,4)(4,5)(5,1)(5,3)(5,4)(6,2)(6,3)(6,6) }
n(A) = 20 ; n(S) = 36
p(A) = n(A)/n(S) = 20/36 (or) 5/9
#Hassan
A = {(1,2)(1,3)(1,5)(2,1)(2,2)(2,4)(2,6)(3,1)(3,3)(3,5)(3,6)(4,2)(4,4)(4,5)(5,1)(5,3)(5,4)(6,2)(6,3)(6,6) }
n(A) = 20 ; n(S) = 36
p(A) = n(A)/n(S) = 20/36 (or) 5/9
#Hassan
Answered by
0
The answer is 20/36 or 5/9
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