two dice are throne simultaneously. the probability of an even number on one and multiple of 3 on the other is
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CASE 1
no. of even numbers we get when the doce is thrown = 3
therefore, p (getting a even number when the dice is thrown) = 3/6 = 1/2
CASE 2
no.of multiples of 3 = 2
therefore, p (getting a multiple of three)
= 2/6
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Total outcomes of one dice- 6
p (getting even number)-3/6=1/2
p (getting multiples of three)=2/6=1/3
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