Question

two dice are thrown. a is th3 event that sum of the numbers on their upper faces lies between 4 and 8. find probability

Answer 1

when two dice r thrown simultaneously . the following r the out comes :
(1, 1),(1, 2),(1, 3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

so there are 36 outcomes
and numbers which have sum between 4 & 8 r 15
so probability is 15 / 36 => 5/12

Answer 2

answer is 22/36 we see the pair of numbers whose sum is between 4 and 8 ..