Question

Two dice are thrown and sum of number on them is marked . find the probability of getting (1) sum 6 (2) sum is perfect square (3) a doublet (4) sum is a perfect cube?

Answer 1

Step-by-step explanation:

hope this will help you

Answer 2

The probability of getting

1) sum 6 is 5/36

2) sum is perfect square is 1/6

3) a doublet is 1/6

4) sum is a perfect square is 5/36

Solution:

Two dice are thrown and their sum of numbers on them is marked

So total number of outcomes = 36

(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)

(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)

(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)

(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)

(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)

(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

The probability of an event is given as:

$\text { probability }=\frac{\text { number of favourable outcomes }}{\text { total number of favourable outcomes }}$

Here total number of favourable outcomes = 36

1) Finding the probability of getting sum of 6:

sum = 6  

favourable outcomes = (1,5)(2,4)(3,3)(4,2)(5,1)

Hence number of favourable outcomes = 5

$probability = \frac{5}{36}$

2) Finding the probability of sum is perfect square:

Sum = perfect square

favourable outcomes = (1,3)(2,2)(3,6)(3,1)(5,4)(6,3)

Hence number of favourable outcomes = 6

$probability = \frac{6}{36} = \frac{1}{6}$

3) Finding the probability of getting a doublet:

favourable outcomes = (1,1)(2,2)(3,3)(4,4)(5,5)(6,6)

Hence number of favourable outcomes = 6

$probability = \frac{6}{36} = \frac{1}{6}$

4) Finding the probability that sum is a perfect cube:

Sum = perfect cube

favourable outcomes = (2,6)(3,5)(4,4)(5,3)(6,2)

Hence number of favourable outcomes = 5

$probability = \frac{5}{36}$

Learn more about dice in probability

In a throw of a pair of dice,the probability of getting a doublet is

https://brainly.in/question/1140270

In throwing 3 dice the probability that at least 2 of the three numbers obtained are same

https://brainly.in/question/6545012