Two dice are thrown at same time determine the probability that the difference of the numbers on the two dice is 2
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different is equal to 2
then chances are (1, 3), (2, 4), (3, 5), (4, 2), (3, 1)
so n of E is equal to 5; n of s is equal to 6 square (36)
p of E is equal to n of e upon n of
P(E) = n(E) /n(S)
=5/36
then chances are (1, 3), (2, 4), (3, 5), (4, 2), (3, 1)
so n of E is equal to 5; n of s is equal to 6 square (36)
p of E is equal to n of e upon n of
P(E) = n(E) /n(S)
=5/36
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