two dice are thrown at the same and the product of numbers appearing on them is noted. find the probabity that the product is a prime number
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Total number of possible outcomes = 36
Total number of favourable outcomes = 6
(1,2) (1,3) (1,5) (2,1) (3,1) (5,1)
Let, E be the event getting the product is prime number.
P(E) = 6/36 = 1/6
Total number of favourable outcomes = 6
(1,2) (1,3) (1,5) (2,1) (3,1) (5,1)
Let, E be the event getting the product is prime number.
P(E) = 6/36 = 1/6
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