Question

two dice are thrown at the same time find the probability that the sum of two numbers appearing on its face is more than or equal to 9

Answer 1

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Two dice tossed simultaneously , than total number of events ( outcomes ) =  6 × 6 = 36

As we can show  all the possible outcomes

{1,1 } , {1,2 } , {1,3 }, {1,4 } ,{1,5 }, {1, 6 } ,

{ 2,1 } , {2 ,2 } , {2,3 }, {2,4 } ,{ 2 ,5 } ,{ 2,6 },  

{ 3,1 } ,{ 3,2 }, { 3,3 } , { 3,4 } ,{ 3 ,5 } ,{ 3,6 } ,

{ 4,1 } ,{ 4 ,2 }, { 4,3 } , { 4,4 } ,{ 4,5 } ,{ 4,6 } ,

{5,1 } {5,2 }, {5,3 } , {5,4 } ,{ 5,5 } , { 5,6 } ,

{6,1 } ,{ 6,2 }, { 6,3 } , { 6, 4 } ,{ 6 ,5 } , { 6,6 }

Possible outcomes =

{ 4,6 },{ 5,5 } , { 5,6 }, { 6, 4 },{ 6 ,5 } , { 6,6 }


No. Of possible outcomes = 6


Probability (P) = 6/36= ⅙

Answer 2

total number of num. which is more than or equal to 9= 10

total number of outcomes= 36

(P) of an event= 11/36