Question

two dice are thrown at the same time find the probability of getting the two numbers appearing on top are
1.consecutive number
2.both prime numbers
3.the product of the number is divisible by 3

Answer 1

Answer:

Total possible outcomes = 36.

(1) consecutive no. are (1,2) , (2,3) , (3,4) ,(4,5), (5,6)

p( consecutive no.)= 5/36

(2) prime no. are (2,2),(2,3),(2,5),(3,2),(3,3)(3,5)(5,2),(5,3), (5,5)

p(both primes ) = 9/36

(3) product of no. divisible by 3=(1,3),(1,6),(2,3),(2,6),(3,2),(3,4),(3,6),(4,3),(4,6),(5,3),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

p(product of a no. divisible by 3)= 17/36