Accountancy, asked by np810124, 1 month ago

Two dice are thrown find the probability 1) sum 8 (2) Sub divisible by 5

plz tell the answer correctly don't tell any other words​

Answers

Answered by llitzmisspaglill703
14

Answer:

The possible outcomes when two dice are thrown together are:

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6).

Therefore, the number of possible outcomes when two dice are thrown is 36.

Now, the possible outcomes of getting a sum equal to 8 is {(2,6),(3,5),(4,4),(5,3),(6,2)}, which means the number of favourable outcome is 5.

Therefore, probability P of getting a sum equal to 8 is:

p=5/36

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