Question

two dice are thrown find the probability of the following event event the sum of the uppermost faces is at least 10​

Answer 1

Answer:

1/6

Step-by-step explanation:

let one die be d1 and another be d2

sample space ={1;1,1;2,1;3,1;4,1;5,1;6,2;1,2;2,2;3,2;4,2;5,2;6,3;1,3;2,3;3,3;4,3;5,3;6,4;1,4;2,;4;3,4;4,4;5,4;6,5;1,5;2,5;3,5;4,5;5,;5;6,6;1,6;2,6;3,6;4,6;5,6;6}

n(s)=36

let A be the event of sun of the uppermost faces is at least 10

A={4;6,5;5,5;6,6;4,6;5,6;6}

n(A)=6

p(A)=n(A)/n(S)

=6/36

=1/6

the probability of the sum of the uppermost faces is at least 10 is 1/6

Hope it will help!

Answer 2

when when a die is thrown then is

and even prime number

2,,4,6

that show the probability in even numbers

in numbers greater than 6

6 that shows the probability in the number

greater than 6

n odd numbers

2,3,5